< Bestimmtes Integral < Standardfunktionen < 1
Berechne das
bestimmte Integral
zur Funktion
f
:
R
≥
3
/
2
⟶
R
,
x
⟼
f
(
x
)
=
x
3
+
1
4
x
−
5
+
cos
x
+
e
−
x
,
{\displaystyle f\colon \mathbb {R} _{\geq 3/2}\longrightarrow \mathbb {R} ,\,x\longmapsto f(x)={\sqrt[{3}]{x}}+{\frac {1}{4x-5}}+\cos x+e^{-x},}
über
[
2
,
7
]
{\displaystyle {}[2,7]}
.
Zur Lösung
,
Alternative Lösung erstellen
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![{\displaystyle f\colon \mathbb {R} _{\geq 3/2}\longrightarrow \mathbb {R} ,\,x\longmapsto f(x)={\sqrt[{3}]{x}}+{\frac {1}{4x-5}}+\cos x+e^{-x},}](../../../../I/92ceaff264e0821d17facfbe3310ad171f5bf885.svg)
![{\displaystyle {}[2,7]}](../../../../I/da8fe3b59a1c647b97ced7d10f6e30c806e38114.svg)