Unzipping a .zip file in Python 2.4.2 (Linux)

Asked Nov 07 '16 at 19:09

Active Nov 07 '16 at 19:17

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I have to use python 2.4.2 to unzip a .zip file. However, the included .zip file in python 2.4.2 does not have either extractall() or extract() attributes. Could someone please tell me how to extract a .zip file with the following structure:

fileABC.zip

- FolderA
    -A.txt
- FolderB
    -B.txt

I just need to extract fileABC.zip to the current directory.

EDIT:

I saw the answer to this question: How to unzip a file with Python 2.4?

However, python 2.4.2 does not seem to have the extract() attribute.

edited May 23 '17 at 12:01

Community

asked Nov 07 '16 at 19:09

M Sidhu

You can still use `read()` and manually write the content to a file. – kichik Nov 07 '16 at 19:11
I found another zipfile 2.4 question with great answers so marked as dup. – tdelaney Nov 07 '16 at 19:15
But that question uses zfile.extract(), which does not exist in 2.4.2. It probably exists in 2.4.4 (Though I'm not sure about that). – M Sidhu Nov 07 '16 at 19:17

Unzipping a .zip file in Python 2.4.2 (Linux)

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