How to search registered user by user id on ejabberd server using asmack in Android?
Following is my code:
//Host & serviceName both are IP_ADDRESS of the ejabberd server.
UserSearchManager usm = new UserSearchManager(connection);
/*Collection<String> services = usm.getSearchServices();
if(services.isEmpty())
throw new Exception("No search services avilable");
String service = services.iterator().next();*/
Form searchForm = usm.getSearchForm(/*service*/"vjud." + connection.getServiceName());
Form answerForm = searchForm.createAnswerForm();
//answerForm.setAnswer("Username", true);
// Tried with only osama also
answerForm.setAnswer("user", "osama@IP_ADDRESS");
ReportedData rd = usm.getSearchResults(answerForm, /*service*/"vjud." + connection.getServiceName());
Iterator<Column> iCols = rd.getColumns();
Iterator<Row> iRows = rd.getRows();
while(iCols.hasNext()) {
Log.i("COLS", iCols.next().getLabel());
}
while(iRows.hasNext()) {
Log.i("ROWS", iRows.next().toString());
}
Following is the output where I am getting columns but not any rows which means it is not getting any user though the user is registered:
10-17 14:09:38.212: I/COLS(30588): Jabber ID
10-17 14:09:38.212: I/COLS(30588): Full Name
10-17 14:09:38.212: I/COLS(30588): Name
10-17 14:09:38.212: I/COLS(30588): Middle Name
10-17 14:09:38.212: I/COLS(30588): Family Name
10-17 14:09:38.212: I/COLS(30588): Nickname
10-17 14:09:38.212: I/COLS(30588): Birthday
10-17 14:09:38.212: I/COLS(30588): Country
10-17 14:09:38.212: I/COLS(30588): City
10-17 14:09:38.212: I/COLS(30588): Email
10-17 14:09:38.212: I/COLS(30588): Organization Name
10-17 14:09:38.212: I/COLS(30588): Organization Unit
I checked this on local ejabberd server on my development machine but still same output.
I tried this answer of stackoverflow getSearchForm returns null when using UserSearch in XMPP with aSmack before which I was getting NullPointerException on following line:
Form answerForm = searchForm.createAnswerForm();
I just wanted to check whether the user has registered. Now, if he has not registered I will send a link to register or else directly send message if registered.
