Checking if form submitted when one form calls another

Question

I have one page with a form that submits to a second page with its own form.

In the second page,

if ($_SERVER['REQUEST_METHOD'] === 'POST') {

always returns true and the if condition executes - I'm not sure if its because its called from a first form itself - but normally that's what I do to check the form is submitted, and it works as expected. Ie, as soon as the page/form opens, it executes the code inside the condition, when obviously it should not.

I need to be able to check in the second form when it is submitted itself ?

Its just a standard short form with its own button

<input type='submit' value='GO!'>

It comes from a first form with its own button

<input type='submit' value='Delete'>

Does the second form action on itself ? Or does it action on another file. Even if the action is set to itself you can add a hidden field for second form and check whether that is set and you will know whether it was submitted — Hanky Panky, Feb 12 '15 at 06:00
yes it actions itself - true I can add another hidden field, but i'm not sure why it's necessary — yoyoma, Feb 12 '15 at 06:01
Because you have to differentiate between the two forms if everything actions on one place. Or you could name the submit button somerhing else — Hanky Panky, Feb 12 '15 at 06:10

score 1 · Answer 1 · answered Feb 12 '15 at 06:04

1

You can try this,

<form method="post" action="">
<input type="submit" name="submit" value="Go!">
</form>

Php code :

  if (isset($_POST['submit'])){

 }

answered Feb 12 '15 at 06:04

Yuva Raj

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score 0 · Answer 2 · answered Feb 12 '15 at 21:40

0

Just noting that I solved this by checking for the name of the submit button, by adding the name:

<input type="submit" name="delete" value="Go!">

Then checking both

if (($_SERVER['REQUEST_METHOD'] === 'POST') && (isset($_POST['delete']))){

answered Feb 12 '15 at 21:40

yoyoma

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Checking if form submitted when one form calls another

2 Answers2