< Term < Einsetzen < 2 <
Aufgabe
Es ist
4
(
y
3
+
5
)
2
+
3
(
y
3
+
5
)
+
7
=
4
(
y
6
+
10
y
3
+
25
)
+
3
y
3
+
15
+
7
=
4
y
6
+
43
y
3
+
122.
{\displaystyle {}{\begin{aligned}4{\left(y^{3}+5\right)}^{2}+3{\left(y^{3}+5\right)}+7&=4{\left(y^{6}+10y^{3}+25\right)}+3y^{3}+15+7\\&=4y^{6}+43y^{3}+122.\end{aligned}}}
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