Q/Archimedes-Prinzip/Multiplikativ/Berechnung/3/Aufgabe/Lösung

Man kann ${}n=7000$ nehmen. Es ist nämlich

{}{\left({\frac {8}{7}}\right)}^{7000}={\left(1+{\frac {1}{7}}\right)}^{7000}\geq 1+7000\cdot {\frac {1}{7}}=1+1000\geq 1000\,.

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