< Primfaktorzerlegung < 10! <
Aufgabe
Es ist
10
!
=
10
⋅
9
⋅
8
⋅
7
⋅
6
⋅
5
⋅
4
⋅
3
⋅
2
⋅
1
=
2
⋅
5
⋅
3
2
⋅
2
3
⋅
7
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2
⋅
3
⋅
5
⋅
2
2
⋅
3
⋅
2
=
2
8
⋅
3
4
⋅
5
2
⋅
7
.
{\displaystyle {}10!=10\cdot 9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1=2\cdot 5\cdot 3^{2}\cdot 2^{3}\cdot 7\cdot 2\cdot 3\cdot 5\cdot 2^{2}\cdot 3\cdot 2=2^{8}\cdot 3^{4}\cdot 5^{2}\cdot 7\,.}
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