Kommutativer Halbring/Rechnung/4/Aufgabe/Lösung

Nach dem Distributivgesetz ist

{}{\begin{aligned}(a+2b)\cdot (2a+3b)&=a\cdot (2a+3b)+2b\cdot (2a+3b)\\&=2a^{2}+3ab+4ab+6b^{2}\\&=2a^{2}+7ab+6b^{2}.\end{aligned}}

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