< Inverse Matrix < 58 <
Aufgabe
(
1
2
0
4
2
1
0
0
3
)
{\displaystyle {}{\begin{pmatrix}1&2&0\\4&2&1\\0&0&3\end{pmatrix}}}
(
1
0
0
0
1
0
0
0
1
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{\displaystyle {}{\begin{pmatrix}1&0&0\\0&1&0\\0&0&1\end{pmatrix}}}
(
1
0
0
4
2
1
0
0
1
)
{\displaystyle {}{\begin{pmatrix}1&0&0\\4&2&1\\0&0&1\end{pmatrix}}}
(
−
1
3
1
3
−
1
9
0
1
0
0
0
1
3
)
{\displaystyle {}{\begin{pmatrix}-{\frac {1}{3}}&{\frac {1}{3}}&-{\frac {1}{9}}\\0&1&0\\0&0&{\frac {1}{3}}\end{pmatrix}}}
(
1
0
0
0
2
1
0
0
1
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{\displaystyle {}{\begin{pmatrix}1&0&0\\0&2&1\\0&0&1\end{pmatrix}}}
(
−
1
3
1
3
−
1
9
4
3
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1
3
4
9
0
0
1
3
)
{\displaystyle {}{\begin{pmatrix}-{\frac {1}{3}}&{\frac {1}{3}}&-{\frac {1}{9}}\\{\frac {4}{3}}&-{\frac {1}{3}}&{\frac {4}{9}}\\0&0&{\frac {1}{3}}\end{pmatrix}}}
(
1
0
0
0
2
0
0
0
1
)
{\displaystyle {}{\begin{pmatrix}1&0&0\\0&2&0\\0&0&1\end{pmatrix}}}
(
−
1
3
1
3
−
1
9
4
3
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1
3
1
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)
{\displaystyle {}{\begin{pmatrix}-{\frac {1}{3}}&{\frac {1}{3}}&-{\frac {1}{9}}\\{\frac {4}{3}}&-{\frac {1}{3}}&{\frac {1}{9}}\\0&0&{\frac {1}{3}}\end{pmatrix}}}
(
1
0
0
0
1
0
0
0
1
)
{\displaystyle {}{\begin{pmatrix}1&0&0\\0&1&0\\0&0&1\end{pmatrix}}}
(
−
1
3
1
3
−
1
9
2
3
−
1
6
1
9
0
0
1
3
)
{\displaystyle {}{\begin{pmatrix}-{\frac {1}{3}}&{\frac {1}{3}}&-{\frac {1}{9}}\\{\frac {2}{3}}&-{\frac {1}{6}}&{\frac {1}{9}}\\0&0&{\frac {1}{3}}\end{pmatrix}}}
Zur gelösten Aufgabe
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