Es ist

${\displaystyle {}{\begin{aligned}[\delta ,\mu _{g}](x)&={\left(\delta \circ \mu _{g}-\mu _{g}\circ \delta \right)}(x)\\&=\delta (gx)-g\delta (x)\\&=g\delta (x)+x\delta (g)-g\delta (x)\\&=x\delta (g).\end{aligned}}}$

${\displaystyle {}[\delta ,\mu _{g}]}$

${\displaystyle {}\delta (g)}$