< Ableitung < pi^x+x^e <
Aufgabe
Es ist
f
′
(
x
)
=
ln
(
π
)
⋅
π
x
+
e
x
e
−
1
.
{\displaystyle {}f'(x)=\ln(\pi )\cdot \pi ^{x}+ex^{e-1}\,.}
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