Lösungen zu den Aufgaben zu Ing:_GdE:_Die_Spannungsquelle

Lösung 1.

${\displaystyle U_{a}=U_{0}-I*R_{i}}$

${\displaystyle U_{a}-U_{0}=-I*R_{i}}$

${\displaystyle {\frac {U_{a}-U_{0}}{-I}}=R_{i}}$

${\displaystyle {\frac {1,32V-1,5V}{-0,38A}}=R_{i}}$

R__i = 0,47 Ω

Lösung 2.

${\displaystyle R_{i}={\frac {U_{a}-U_{b}}{I_{b}-I_{a}}}}$

Diese Formel gilt für Spannungsquellen, nicht für Verbraucher

${\displaystyle R_{i}={\frac {11,9V-11,72V}{18A-10A}}}$

${\displaystyle R_{i}={\frac {0,18V}{8A}}}$

R__i = 0{,}0225 Ω

${\displaystyle U_{a}=U_{0}-I_{a}*R_{i}}$

${\displaystyle U_{0}=U_{a}+I_{a}*R_{i}}$

U₀ = 11,9 V + 10 A * 0,0225 Ω

U₀ = 12,125 V