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σ
7
(
n
)
=
σ
3
(
n
)
+
120
∑
k
=
1
n
−
1
σ
3
(
n
−
k
)
σ
3
(
k
)
{\displaystyle \sigma _{7}(n)=\sigma _{3}(n)+120\sum _{k=1}^{n-1}\sigma _{3}(n-k)\,\sigma _{3}(k)}
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