How to slice a string to fetch characters at odd and even position

Question

I have a string:

'ABCDEFGHIJKLMNOPQRSTUVWXYZ'

I need to print the strings with the characters present at odd and even position in the above string.

For example:

Possible duplicate of [Python program to split a list into two lists with alternating elements](https://stackoverflow.com/questions/1442782/python-program-to-split-a-list-into-two-lists-with-alternating-elements) — Aran-Fey, Mar 29 '18 at 19:18

score 10 · Answer 1 · edited Dec 02 '20 at 22:10

You need to use string slicing. For example:

>>> my_str = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'

# For odd
>>> my_str[::2]
'ACEGIKMOQSUWY'

# For even
>>> my_str[1::2]
'BDFHJLNPRTVXZ'

General syntax of string slicing is string[start:end:jump] where:

start: is the starting index for slicing the string. Empty value means start of the string i.e. index 0
end: is the index till which you want to slice the string. Empty value means end of the string
jump: is used to jump the elements from start such that you'll get values in the order start, start+jump, start+2*jump, so on till your string reaches end. Empty value means 1

1 Answers1