How to get tag name in XSLT?

Question

I made a simple example of xslt. I want to show tag name in h2. How to show the tag name using xslt?

Here is my code: Link

I used this

<!--h1><xsl:value-of select="abc/p/name(.)"/></h1-->

It gives me an error. Why?

Expected output:

"P" (first tag inside abc tag)

Please post your code in the question itself, not in external links. — michael.hor257k, Dec 08 '16 at 06:22

score 1 · Accepted Answer · answered Dec 08 '16 at 06:21

1

Your attempt:

<xsl:value-of select="abc/p/name(.)"/>

will work, provided your processor supports XSLT 2.0.

In XSLT 1.0, you need to do:

<xsl:value-of select="name(abc/p)"/>

which will also work in XSLT 2.0, of course.

answered Dec 08 '16 at 06:21

michael.hor257k

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could you please tell me why call function is not working https://plnkr.co/edit/TN1BN5Yao5Z63RDcBGlN?p=preview – user944513 Dec 08 '16 at 06:24
I suggest you post a separate question. Hint: `xsl:call-template` must be in a template that matches something in your input.. – michael.hor257k Dec 08 '16 at 06:33
ok ..here is my Question http://stackoverflow.com/questions/41033174/why-function-is-not-called-in-xslt – user944513 Dec 08 '16 at 06:34

score 0 · Answer 2 · edited May 23 '17 at 12:13

First of all: add a <xsl:template match="text()" /> to avoid unwanted output.

Then I would change the first template to match you abc because this is the interesting parent node. If you want any child of the node, use abc/*. Then the template will match abs/p and abc/catalog. But you only want the first child, right? So use abc/*[1]. This will only match abc/p. And now you can do the name(.) or local-name().

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="abc/*[1]">
    <html>
      <body>
       <h1><xsl:value-of select="local-name()"/></h1>
      </body>
    </html>
  </xsl:template>

  <xsl:template match="text()" />

</xsl:stylesheet>

Your XML-File

<abc>
    <p test='ravi'>test123</p>
    <catalog>
        <cd>
            <title>Empire Burlesque</title>
            <artist>Bob Dylan</artist>
            <country>USA</country>
            <company>Columbia</company>
            <price>10.90</price>
            <year>1985</year>
        </cd>
    </catalog>
</abc>

Read this: https://stackoverflow.com/a/585290/5413817

the tamplate match everything unmatched before. It is a kind of `default` in a switch-case. — Marcus, Dec 08 '16 at 08:07

How to get tag name in XSLT?

2 Answers2