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What is the difference between using & in these two cases?

  1. Calling fun1:

    fun1(&toproc)

  2. In function definition: 

    def fun1(&toblock)
  # ...
end

Is it that when receiving a parameter with &toblock it is converted to a Proc and for the other case it is converted to a block?

Jordan Running
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new user20
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  • Not quite a duplicate, but the answers to this question answer your question: http://stackoverflow.com/questions/28439734/purpose-of-ampersand-in-ruby-for-procs-and-calling-methods – Dave Schweisguth May 24 '16 at 21:53

1 Answers1

3

In the first case, toproc is a variable which contains a proc, or will be cast to a proc if not.

In the second case, we are explicitly declaring that the function takes a block argument, which we can refer to by the name toblock.

This article gives a pretty good explanation: http://www.skorks.com/2013/04/ruby-ampersand-parameter-demystified/

Fred Willmore
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